非线性屈曲分析

/POST26
NSOL,2,1,U,Y ! STORE UY DISPLACEMENT OF NODE 1
NSOL,3,2,U,Y ! STORE UY DISPLACEMENT OF NODE 2
PROD,4,1,,,LOAD,,,4*250 ! TOTAL LOAD IS 4*250 DUE TO QUARTER SYMMETRY
PROD,5,2,,,,,,-1 ! CHANGE SIGNS OF THE DISPLACEMENT VALUES
PROD,6,3,,,,,,-1
*GET,UY1,VARI,2,EXTREM,VMIN
*GET,UY2,VARI,3,EXTREM,VMIN
PRVAR,2,3,4 ! PRINT STORED INFORMATION
/AXLAB,X, DEFLECTION (MM)
/AXLAB,Y, TOTAL LOAD (N)
/GRID,1
/XRANGE,0,35
/YRANGE,-500,1050
XVAR,5
PLVAR,4 ! PLOT LOAD WITH RESPECT TO -UY OF NODE 1
/NOERASE
XVAR,6
PLVAR,4 ! PLOT LOAD WITH RESPECT TO -UY OF NODE 2
/ERASE
*DIM,LABEL,CHAR,2,2
*DIM,VALUE,,2,3
LABEL(1,1) = 'UY @A ','UY @B '
LABEL(1,2) = 'mm ','mm '
*VFILL,VALUE(1,1),DATA,-30,-26
*VFILL,VALUE(1,2),DATA,UY1,UY2
*VFILL,VALUE(1,3),DATA,ABS(UY1/30) ,ABS(UY2/26 )

*VWRITE,LABEL(1,1),LABEL(1,2),VALUE(1,1),VALUE(1,2),VALUE(1,3)

/OUT
FINISH
*LIST,vm17,vrt
/DELETE,SCRATCH

各位大侠这是一个非线性屈曲分析的例题中/post26部分语句，有谁能帮解释一下吗？