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请问abaqus子程序sigini怎么用?怎么在inp里添加 求例子
例子如下:
*INCLUDE,INPUT=initial.ipe500
*INITIAL CONDITIONS,TYPE=STRESS,USER
*USER SUBROUTINES
SUBROUTINE SIGINI(SIGMA,COORDS,NTENS,NCRDS,NOEL,NP,LA,M,LR,RE)
INCLUDE ‘ABA_PARAM.INC’
DIMENSION SIGMA(NTENS),COORDS(NCRDS)
CHARACTER*8 RE
IF(NOEL.GE.1.AND.NOEL.LE.100)THEN
IF(M.EQ.1.OR.M.EQ.17.OR.M.EQ.33.OR.M.EQ.49)THEN
SIGMA(1)=-7.050
ELSE IF(M.EQ.2.OR.M.EQ.16.OR.M.EQ.34.OR.M.EQ.48)THEN
SIGMA(1)=-5.2875
ELSE IF(M.EQ.3.OR.M.EQ.15.OR.M.EQ.35.OR.M.EQ.47)THEN
SIGMA(1)=-3.525
ELSE IF(M.EQ.4.OR.M.EQ.14.OR.M.EQ.36.OR.M.EQ.46)THEN
SIGMA(1)=-1.7625
ELSE IF(M.EQ.5.OR.M.EQ.13.OR.M.EQ.37.OR.M.EQ.45)THEN
SIGMA(1)=0.
ELSE IF(M.EQ.6.OR.M.EQ.12.OR.M.EQ.38.OR.M.EQ.44)THEN
SIGMA(1)=1.7625
ELSE IF(M.EQ.7.OR.M.EQ.11.OR.M.EQ.39.OR.M.EQ.43)THEN
SIGMA(1)=3.525
ELSE IF(M.EQ.8.OR.M.EQ.10.OR.M.EQ.40.OR.M.EQ.42)THEN
SIGMA(1)=5.2875
ELSE IF(M.EQ.9.OR.M.EQ.41)THEN
SIGMA(1)=7.050
ELSE IF(M.EQ.18.OR.M.EQ.32)THEN
SIGMA(1)=5.3439
ELSE IF(M.EQ.19.OR.M.EQ.31)THEN
SIGMA(1)=3.6378
ELSE IF(M.EQ.20.OR.M.EQ.30)THEN
SIGMA(1)=1.9317
ELSE IF(M.EQ.21.OR.M.EQ.29)THEN
SIGMA(1)=0.2256
ELSE IF(M.EQ.22.OR.M.EQ.28)THEN
SIGMA(1)=-1.4805
ELSE IF(M.EQ.23.OR.M.EQ.27)THEN
SIGMA(1)=-3.1866
ELSE IF(M.EQ.24.OR.M.EQ.26)THEN
SIGMA(1)=-4.8927
ELSE IF(M.EQ.25)THEN
SIGMA(1)=-6.5988
ENDIF
RETURN
END
在分析步之前添加*INITIAL CONDITIONS,TYPE=STRESS,USER
楼主的问题解决了嘛
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例子如下:
*INCLUDE,INPUT=initial.ipe500
*INITIAL CONDITIONS,TYPE=STRESS,USER
*USER SUBROUTINES
SUBROUTINE SIGINI(SIGMA,COORDS,NTENS,NCRDS,NOEL,NP,LA,M,LR,RE)
INCLUDE ‘ABA_PARAM.INC’
DIMENSION SIGMA(NTENS),COORDS(NCRDS)
CHARACTER*8 RE
IF(NOEL.GE.1.AND.NOEL.LE.100)THEN
IF(M.EQ.1.OR.M.EQ.17.OR.M.EQ.33.OR.M.EQ.49)THEN
SIGMA(1)=-7.050
ELSE IF(M.EQ.2.OR.M.EQ.16.OR.M.EQ.34.OR.M.EQ.48)THEN
SIGMA(1)=-5.2875
ELSE IF(M.EQ.3.OR.M.EQ.15.OR.M.EQ.35.OR.M.EQ.47)THEN
SIGMA(1)=-3.525
ELSE IF(M.EQ.4.OR.M.EQ.14.OR.M.EQ.36.OR.M.EQ.46)THEN
SIGMA(1)=-1.7625
ELSE IF(M.EQ.5.OR.M.EQ.13.OR.M.EQ.37.OR.M.EQ.45)THEN
SIGMA(1)=0.
ELSE IF(M.EQ.6.OR.M.EQ.12.OR.M.EQ.38.OR.M.EQ.44)THEN
SIGMA(1)=1.7625
ELSE IF(M.EQ.7.OR.M.EQ.11.OR.M.EQ.39.OR.M.EQ.43)THEN
SIGMA(1)=3.525
ELSE IF(M.EQ.8.OR.M.EQ.10.OR.M.EQ.40.OR.M.EQ.42)THEN
SIGMA(1)=5.2875
ELSE IF(M.EQ.9.OR.M.EQ.41)THEN
SIGMA(1)=7.050
ELSE IF(M.EQ.18.OR.M.EQ.32)THEN
SIGMA(1)=5.3439
ELSE IF(M.EQ.19.OR.M.EQ.31)THEN
SIGMA(1)=3.6378
ELSE IF(M.EQ.20.OR.M.EQ.30)THEN
SIGMA(1)=1.9317
ELSE IF(M.EQ.21.OR.M.EQ.29)THEN
SIGMA(1)=0.2256
ELSE IF(M.EQ.22.OR.M.EQ.28)THEN
SIGMA(1)=-1.4805
ELSE IF(M.EQ.23.OR.M.EQ.27)THEN
SIGMA(1)=-3.1866
ELSE IF(M.EQ.24.OR.M.EQ.26)THEN
SIGMA(1)=-4.8927
ELSE IF(M.EQ.25)THEN
SIGMA(1)=-6.5988
ENDIF
ENDIF
RETURN
END